• Asignatura: Matemáticas
  • Autor: sandrukarrero08
  • hace 2 años

a) 15 : 5-6:3+ 49 : 7 - 22:2
b) [36 : (-4) - 3.2] : (-2 - 4 + 1)
c) [18:3+8:2-5.2] . (4+5 - 3)
d) 6 + [7 - 5 - (-2) + (-4)]
e) [64:8 - 25 : 5] . 2 - [16 : 4 + 27:9] : 7
f) (5 + 3): 2 - (7 - 4): 3
g) 6 : (2 + 1) - [1 + (2.3:6). 7] + 7
h) [6 • (4 - 6:2)] - [2 - (1 - 10): 3]
i) (1 - 7): (2 - 4) + (12 - 10) : (1-2)
j) 4-6: (6-4) - [16: (9 - 1) - 3]​

Respuestas

Respuesta dada por: lucasbarrosomolina
5

Respuesta:

Explicación paso a paso:

A. 15/5-6:3+49/7-22/2 = 3-2+7-11 = 1+7-11 = 8-11 = -3

B. [36/(-4)-3*2]/(-2-4+1) = (-9-6)/(-6+1) = -15/(-5) = 3

C. (18/3+8/2-5*2)*(4+5-3) = (6+4-10)*(9-3) = (10-10)*6 = 0*6 = 0

D. 6+[7-5-(-2)+(-4)] = 6+7-5+2-4 = 13-5+2-4 = 8+2-4 = 10-4 = 6

E. (64:8-25/5)*2-(16/4+27/9)/7 = (8-5)*2-(4+3) = 3*2-7 = 6-7 = -1

F. (5+3)/2-(7-4)/3 = 8/2-3/3 = 4-1 = 3

G. 6/(2+1)-[1+(2*3/6)*7]+7 = 6/3-(1+6/6*7+7) = 2-(1+1*7+7) = 2-(1+7+7)=2-(8+7)= 2-15 = -1

H. [6*(4-6/2)]-[2-(1-10)/3] = [6*(4-3)]-(2+9/3) = (6*1)-(2+3) = 6-5 = 1

I. (1-7)/(2-4)+(12-10)/(1-2) = -6/(-2)+2/(-1) = 3+(-2) = 3-2 = 1

J. 4-6/(6-4)-[16/(9-1)-3]​ = 4-6/2-(16/8-3) = 4-3-(2-3) = 1-(-1) = 1+1 =2


sandrukarrero08: Muchas gracias!
gaivi26: de nada gonorreaaa
sandrukarrero08: gonorrea?
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