Question

resolver: (x-5)/7≤- 2x+3

Answer 1

$\frac{(x-5)}{7} \leq -2x+3\\x-5\le \:-14x+21\\x-5+5\le \:-14x+21+5\\x\le \:-14x+26\\x+14x\le \:-14x+26+14x\\15x\le \:26\\\frac{15x}{15}\le \frac{26}{15}\\Respuesta: x\le \frac{26}{15}$

Answer 2

Respuesta:

26/15

Explicación paso a paso:

(x-5)/7≤- 2x+3

x-5< - 14x+21

x+14x< 21+5

15x < 26

x< 26/15