Question

Si: tg(α + β) = 3 y tgβ = 2
Calcular: tgα

Answer 1

Explicación paso a paso:

$tan( \alpha + \beta ) = \frac{tan \alpha + \tan( \beta ) }{1 - \tan( \alpha ) \tan( \beta ) }$

$3 = \frac{ \tan( \alpha ) + 2}{1 - \tan( \alpha ) 2}$

$3 - 6 \tan( \alpha ) = \tan( \alpha ) + 2 \\ 1 = 7 \tan( \alpha ) \\ \frac{1}{7} = \tan( \alpha )$