Question

Ayúdenme porfa :'v



(5/3-^3)^2 - √ 3/2(4/5+7/10)
Ahí está de esa manera tmb☝

Answer 1

Respuesta:

$\bold{RADICACION}$

$\boxed{\left(\frac{5}{3}^{-3}\right)^2\:-\:\sqrt{\frac{3}{2}\:\left(\frac{4}{5}+\frac{7}{10}\right)}}$

$\left(\frac{5}{3}^{-3}\right)^2\:=\frac{3^6}{5^6}$

$\sqrt{\frac{3}{2}\left(\frac{4}{5}+\frac{7}{10}\right)}=\frac{3}{2}$

$\frac{3^6}{5^6}-\frac{3}{2}$$\frac{3^6}{5^6}=\frac{729}{15625}$

$\frac{729}{15625}-\frac{3}{2}$

Multiplicamos

$729\times2=1458$

$15625\times2=31250$

$\frac{1458}{31250}-\frac{46875}{31250}=\frac{1458-46875}{31250}$

$1458-46875=-45417$

Solución

$\frac{-45417}{31250}=-\frac{45417}{31250}$

$\boxed{-\frac{45417}{31250}}$

Saludos...