Question

[cos(A)sec(A)]+[1sec2(A)tan2(A)]
ayudaaaaaa! urgueeeee
quien responda ya!

Answer 1

Respuesta:

$[cos(A)sec(A)]+[1sec2(A)tan2(A)]\\\\=\cos \left(A\right)\sec \left(A\right)+1\cdot \sec \left(2\right)A\tan \left(2\right)A\\\\=\cos \left(A\right)\sec \left(A\right)+\frac{\tan \left(2\right)A^2}{\cos \left(2\right)}\\\\ =\frac{\tan \left(2\right)A^2}{\cos \left(2\right)}+\frac{\cos \left(A\right)\sec \left(A\right)\cos \left(2\right)}{\cos \left(2\right)}\\\\=\frac{\tan \left(2\right)A^2+\cos \left(A\right)\sec \left(A\right)\cos \left(2\right)}{\cos \left(2\right)}$

$=\frac{\tan \left(2\right)A^2+\cos \left(2\right)}{\cos \left(2\right)}$