Question

me pueden ayudar con este ejercicio por favor

5-[3-2(8-7+1)+(4+3) =
5-[3-2(2)+(1)] =
5 -[3 -4+1] =
5 -[0]= 5​

Answer 1

Respuesta:

5-[3-2(8-7+1)+(4+3) =

=5−[3−2⋅(1+1)+(7))=  

=5−[3−2⋅(2)+(7))=

=5−[3−4+(7))=

=5−[−1+(7))=

=5−[6)=

=−1

5-[3-2(2)+(1)] =

=5−[3−4+(1)]=  

=5−[−1+(1)]=

=5−[0]=

=5

5 -[3 -4+1] =

=5−[−1+1]=  

=5−[0]=

=5

5 -[0]= 5​

=5-0

=5