Question

calcula z = (x+2)² +(x+3)²-2x(x+5)

Answer 1

Respuesta:

z = 13

Explicación paso a paso:

$\left(x+2\right)^2+\left(x+3\right)^2-2x\left(x+5\right)$

$x^2+4x+4+\left(x+3\right)^2-2x\left(x+5\right)$

$x^2+4x+4+x^2+6x+9-2x\left(x+5\right)$

$x^2+4x+4+x^2+6x+9-2x^2-10x$

$x^2+x^2-2x^2+4x+6x-10x+4+9$

$4x+6x-10x+4+9$

$4+9$

$13$