Question

(-a)×(-a)×(-a) =
b×b×b×(-4)=
4×(2a+5)=
(3m-1)×(-2)=
(y+2)×(y-2)=
b×1×a=
C×(-1)×a×b=
5m÷8=
(5+4)÷3=
a÷4+5÷c=
y÷2-z×4=
10×m+n÷5=
z÷5+b×c÷2=
Alguien me ayuda xfis​

Answer 1

Respuesta:

(-a)×(-a)×(-a) =

=(−a)2⋅−a=  

=(−a)3=

=−a3

b×b×b×(-4)=

=(b)2b⋅(−4)=  

=−4b3

4×(2a+5)=

=8a+20

(3m-1)×(-2)=

=−6m+2

(y+2)×(y-2)=

=y2−4

b×1×a=

=ba

C×(-1)×a×b=

=−cab

5m÷8=

=5m⋅18=  

=58m

(5+4)÷3=

=(9):3=  

=3

a÷4+5÷c=

=14a+5⋅1c=  

=14a+5c=

=(a⋅c)+(5⋅4)4c=

=ac+20⁄4c

y÷2-z×4=

=y:2−4z=  

=12y−4z

10×m+n÷5=

=10m+15n

z÷5+b×c÷2=

=15z+12bc