Question

x² - 2x + 2=0 por factorizacion

Answer 1

Respuesta:

$x^{2} - 2x + 2 = 0\\(x - \sqrt{2} -2 )(x +\sqrt{2} - 2 ) = 0$

Explicación paso a paso:

$x^{2} - 2x + 2 = 0\\x^{2} - 2x + 4 - 2 = 0\\(x - 2 )^{2} - 2 = 0\\(x - 2 )^{2} = 2\\\\x - 2 = + \sqrt{2} \\ x = + \sqrt{2} + 2\\\\x - 2 = - \sqrt{2}\\x = -\sqrt{2} + 2$

$x^{2} - 2x + 2 = 0\\(x - \sqrt{2} -2 )(x +\sqrt{2} - 2 ) = 0$