• Asignatura: Matemáticas
  • Autor: camilaparra1998
  • hace 9 años

1.-(4x-6+5x)+(9-5+3-2x)=7x-(1-6x)
2.12y=3(3y-5)
3.2(b+2)-5(2b-3)=3
4. 7-6(c-1)+3(3-4c)=7+(7c-4)

Respuestas

Respuesta dada por: charls1
0
-(4x-6+5x)+(9-5+3-2x) = 7x-(1-6x)
-(9x-6)+(7-2x) = 7x-1+6x
-9x+6+7-2x = 7x-1+6x
-11x + 13 = 13x-1
13x+11x = 13+1
24x = 14
x = 7/12

12y = 3(3y-5)
12y = 9y - 15
12y - 9y = 15
3y = 15
y = 5

2(b+2)-5(2b-3) = 3
2b + 4 - 10b + 15 = 3
-8b + 19 = 3
-8b = -16
b = 2

7-6(c-1)+3(3-4c) = 7+(7c-4)
7 - 6c + 6 + 9 - 12c = 7 + 7c - 4
22 - 18c = 3 + 7c
22-3 = 18c + 7c
25c = 19
c = 19/25
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