Question

M = (sen45°) ctg (53/2)+ log10sen30° − sen237°

Answer 1

Respuesta:

$\text{M}=\left(\sin \left(45^{\circ \:}\right)\right)\cot \left(\frac{53}{2}\right)+\log _{10}\left(10\right)\sin \left(30^{\circ \:}\right)-\sin \left(237^{\circ \:}\right)$

Eliminamos paréntesis

$\text{M}=\sin \left(45^{\circ \:}\right)\cot \left(\frac{53}{2}\right)+\log _{10}\left(10\right)\sin \left(30^{\circ \:}\right)-\sin \left(237^{\circ \:}\right)$

$\sin \left(45^{\circ \:}\right)\cot \left(\frac{53}{2}\right)=\frac{\sqrt{2}\cot \left(\frac{53}{2}\right)}{2}$

$\log _{10}\left(10\right)\sin \left(30^{\circ \:}\right)=\frac{1}{2}$

$\text{M}=\frac{\sqrt{2}\cot \left(\frac{53}{2}\right)}{2}+\frac{1}{2}-\sin \left(237^{\circ \:}\right)$

Combinamos fracciones usando el MCD

$\frac{\sqrt{2}\cot \left(\frac{53}{2}\right)+1}{2}$

Solución

$\boxed{\text{M}=\frac{\sqrt{2}\cot \left(\frac{53}{2}\right)+1}{2}-\sin \left(237^{\circ \:}\right)}$

Saludos...