Question

ayudenme
ayuda ayuda ayuda​

Answer 1

Respuesta:

Hola!

Procedimiento:

1.

$\frac{2}{3} x - \frac{1}{2} = \frac{4}{3} - x\\\\\frac{2x}{3} - 1 .\frac{1}{2} = \frac{4}{3} - x\\\\\frac{2x}{3} - \frac{1}{2} = \frac{4}{3} - x\\\\\frac{2x}{3} + \frac{3(-\frac{1}{2}) }{3} = \frac{4}{3} - x\\\\\frac{2x + 3(-\frac{1}{2}) }{3} = \frac{4}{3} - x\\\\\frac{2x-\frac{3}{2} }{3} = \frac{4}{3} - x \\\\\frac{2x-\frac{3}{2} }{3} = -x + \frac{4}{3} \\\\\frac{5x - \frac{3}{2} }{3} = \frac{4}{3} \\\\5x - \frac{3}{2} = 4\\\\5x = \frac{11}{2} \\\\Simplifica:\\\\x = \frac{11}{10}$

2.

$\frac{2x}{3} + \frac{16}{3} = -\frac{4x}{2} \\\\\frac{2x + 3 . \frac{16}{3} }{3} = \frac{-4x}{2} \\\\\frac{2x+16}{3} = \frac{-4x}{2} \\\\\frac{2x + 16}{3} = -2x\\\\\frac{8x + 16}{3} = 0\\\\3(\frac{8x +16}{3} ) = 0\\\\8x + 16 = 0\\8x = -16\\x = \frac{-16}{8} \\\\x = -2$

ESPERO QUE TE AYUDE

Answer 2

Respuesta:

Hola!

Respuestas:

1.

$x = \frac{11}{10}$

2.

$x = -2$

ESPERO TE SIRVA