Question

3√2+3×2-(2)^2+3÷(-5+4)-√9+16​

Answer 1

$3.\sqrt{2}+3.2-2^2+3:(-5+4)-\sqrt{9}+16=$

$3\sqrt{2} + 6 - 4 + 3: (-1) - 3 + 16 =\\3\sqrt{2} + 6 - 4 + (-3) - 3 + 16 =\\3\sqrt{2} + 2 + (-6) + 16 =\\3\sqrt{2} + 2 - 10 = 3\sqrt{2} + (-8)$