Question

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Answer 1

Respuesta:

Espero te sirva!!!!!!!!!!

Answer 2

C- $(\frac{3}{4})^2 = (\frac{3^2}{4^2}) \\\\ \frac{9}{16} = \frac{9}{16}$

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D- $\sqrt{\frac{4}{9} } = \frac{\sqrt{4} }{\sqrt{9} }\\\\\frac{2}{3} =\frac{2}{3}$

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E- $\frac{\sqrt[3]{-8} }{\sqrt[4]{625} } = \frac{-2}{5}\\\\\frac{-2}{5} = \frac{-2}{5}$

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F- $(\frac{\sqrt{3} }{4})^2 = \frac{(\sqrt{3} )^2}{4^2}\\\\\\\frac{\sqrt{9} }{16} = \frac{\sqrt{9} }{16}\\\\\frac{3}{16} = \frac{3}{16}$

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G- $(-\frac{2}{5})^3 = -\frac{2^3}{5^3}\\\\-\frac{8}{125} = -\frac{8}{125}$

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H- $(-\frac{3}{4})^-^2 = (-\frac{4}{3})^2\\\\(-\frac{4}{3})^2 = (-\frac{4}{3})^2\\\\\frac{16}{9} = \frac{16}{9}$

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I- $(\frac{3}{4})^-^2 = \frac{4^2}{3^2}\\\\(\frac{4}{3})^2 = \frac{4^2}{3^2}\\\\\frac{16}{9} = \frac{16}{9}$