Question

Tema: Ecuación Exponencial

Answer 1

Explicación paso a paso:

${2}^{x + 1} \times {4}^{x + 2} \times {8}^{x + 3} = 1$

${2}^{x + 1} \times {2}^{2(x + 2)} \times {2}^{3(x + 3)} = 1$

${2}^{x + 1} \times {2}^{2x + 4} \times {2}^{3x + 9} = 1$

${2}^{x + 1 + 2x + 4 + 3x + 9} = 1$

${2}^{6x + 14} = (2) {}^{0}$

$6x + 14 = 0$

$6x = - 14$

$x = \frac{ - 14}{6}$

$x = - \frac{7}{3}$

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${4}^{x + 2} = ( {2}^{2} ) {}^{x + 2} = {2}^{2x + 4}$

${8}^{x + 3} = ( {2}^{3} ) {}^{x + 3} = {2}^{3x + 9}$

${2}^{0} = 1$