Question

AA+ BB + CC=ABC ayudaaaa​

Answer 1

Respuesta:

Expresamos AA + BB + CC y lo elevamos a la 2

• AA + BB + CC = ABC

• A² + B² + C² = ABC

ABC - ABC = 0

A² - BCA + B² + C² = 0

Resolvemos mediante formula general

$\boxed{\text{A}_{1,\:2}=\frac{-\left(-\text{BC}\right)\pm \sqrt{\left(-\text{BC}\right)^2-4\cdot \:1\cdot \left(\text{B}^2+\text{C}^2\right)}}{2\cdot \:1}}$

$\sqrt{\left(-\text{BC}\right)^2-4\cdot \:1\cdot \left(\text{B}^2+\text{C}^2\right)}=\sqrt{\text{B}^2\text{C}^2-4\left(\text{B}^2+\text{C}^2\right)}$

$\text{A}_{1,\:2}=\frac{-\left(-\text{BC}\right)\pm \sqrt{\text{B}^2\text{C}^2-4\left(\text{B}^2+\text{C}^2\right)}}{2\cdot \:1}$

Separamos soluciones

$\text{A}_1=\frac{-\left(-\text{BC}\right)+\sqrt{\text{B}^2\text{C}^2-4\left(\text{B}^2+\text{C}^2\right)}}{2\cdot \:1}$

$\text{A}_2=\frac{-\left(-\text{BC}\right)-\sqrt{\text{B}^2\text{C}^2-4\left(\text{B}^2+\text{C}^2\right)}}{2\cdot \:1}$

Resolvemos y multiplicamos

$\text{A}_1\frac{-\left(-\text{BC}\right)+\sqrt{\text{B}^2\text{C}^2-4\left(\text{B}^2+\text{C}^2\right)}}{2\cdot \:1}=\frac{\text{BC}+\sqrt{\text{B}^2\text{C}^2-4\left(\text{B}^2+\text{C}^2\right)}}{2\cdot \:1}$

$2\cdot \:1=2$

$\frac{\text{BC}+\sqrt{\text{B}^2\text{C}^2-4\left(\text{B}^2+\text{C}^2\right)}}{2}$

$\text{A}_2\frac{-\left(-\text{BC}\right)-\sqrt{\text{B}^2\text{C}^2-4\left(\text{B}^2+\text{C}^2\right)}}{2\cdot \:1}=\frac{\text{BC}-\sqrt{\text{B}^2\text{C}^2-4\left(\text{B}^2+\text{C}^2\right)}}{2\cdot \:1}$

$2\cdot \:1=2$

$\frac{\text{BC}-\sqrt{\text{B}^2\text{C}^2-4\left(\text{B}^2+\text{C}^2\right)}}{2}$

Soluciones

• $\text{A}_1=\frac{\text{BC}+\sqrt{\text{B}^2\text{C}^2-4\left(\text{B}^2+\text{C}^2\right)}}{2}}$

• $\text{A}_2=\frac{\text{BC}-\sqrt{\text{B}^2\text{C}^2-4\left(\text{B}^2+\text{C}^2\right)}}{2}}$

Saludos...