Question

04. Hallar “x” (agudo), de:
$Tg\frac{7X+1}{2} Ctg\frac{2X+27}{3} =1$

Answer 1

Explicación paso a paso:

$recordar \\ \tan( \alpha ) \cot( \alpha ) = 1 \\ por \: lo \: tanto \\ \frac{7x + 1}{2} = \frac{2x + 27}{3} \\ 3(7x + 1) = 2(2x + 27) \\ 21x + 3 = 4x + 54 \\ 21x - 4x = 54 - 3 \\ 17x = 51 \\ x = \frac{51}{17} \\ x = 3$