Question

Ayudenme Doy Corona con estas ecuaciones si no sabes no resspondas gracias
x/x+4-x/x+2=12/(x+4)(x+12)

Answer 1

Respuesta:

x/x+4-x/x+2 = 12/(x+4)(x+12)

m.c.m(x+4,x+2,x+12) = x^3+18x^2+80x+96

(x^3+18x^2+80x+96)(x/(x+4)) - x^3+18x^2+80x+96(x/(x+2)) = x^3+18x^2+80x+96(12/((x+4)(x+12))

((x^2+14x+24)(x))-((x^2+16x+48)(x)) = ((x+2)(12))

x^3+14x^2+24x-(x^3+16x^2+48x) = 12x+24

x^3+14x^2+24x-x^3-16x^2-48x = 12x+24

(1-1)x^3+14x^2+24x-16x^2-48x = 12x+24

14x^2+24x-16x^2-48x = 12x+24

(14-16)x^2+(24-48)x = 12x+24

-2x^2+(-2x) = 12x+24

-2x^2-2x = 12x+24

-2x^2-2x = 12x+24

-2x^2-2x-12x = 12x+24-12x

-2x^2-(2+12)x = 24

- 2x^2-14x = 24

-2x^2-14x-24 = 24-24

-2x^2-14x-24 = 0

-(2x^2+14x+24 )/-1 = 0/-1

2x^2+14x+24 = 0

2x^2/2+14x/2+24/2 = 0/2

x^2+7x+12 = 0

Factorizo :

x^2+7x+12 = 0

x^2+3x+4x+12 = 0

x(x+3)+4(x+3) = 0

(x+3)(x+4) = 0

X1 = -3 y X2 = -4

Explicación paso a paso: