Question

mediante un diagrama de árbol determina cuántos resultados posibles hay al lanzar dos dados coloca a continuación la representación​

Answer 1

Respuesta:

Answer:

A) 0.15

B) 0.36

Step-by-step explanation:

First Box consist 1 red pills and 19 blue pills

second box consist 6 red pills and 14 blue pills

Third box consist 2 red pills and 18 blue pills

a) Prob ( randomly chosen pill is red) = \frac{1}{3} \times \frac{1}{20} + \frac{1}{3} \times \frac{6}{20} + \frac{1}{3} \times \frac{2}{20}=

3

1

×

20

1

+

3

1

×

20

6

+

3

1

×

20

2

\frac{1}{60} (1+6+2) = 0.15

60

1

(1+6+2)=0.15

b)Prob ( 1 reds and 10 blue pilss) =\frac{1}{3} \frac{^1C_1\times ^{19}C_{10}}{^{20}C_{11}} + \frac{1}{3} \frac{^6C_1\times ^{14}C_{10}}{^{20}C_{11}} + \frac{1}{3} \frac{^2C_1\times ^{18}C_{10}}{^{20}C_{11}}

3

1

20

C

11

1

C

1

×

19

C

10

+

3

1

20

C

11

6

C

1

×

14

C

10

+

3

1

20

C

11

2

C

1

×

18

C

10

= \frac{1}{3} 1.106 = 0.368=

3

1

1.106=0.368