Question

hallar la suma del polimonios 5/6 X^2-2/3 Y^2+3/4 XY; -1/2 XY-1/6 X^2+1/8 Y²; 5/6 XY-1/3 X^2+1/4 Y²

Answer 1

Respuesta:

       $\frac{2}{6} x^{2} +\frac{13}{12} xy-\frac{7}{24} y^{2}$

Explicación paso a paso:

$( \frac{5}{6} x^{2} -\frac{2}{3} y^{2} +\frac{3}{4} xy)+(-\frac{1}{2} xy-\frac{1}{6 }x^{2} +\frac{1}{8} y^{2} )+(\frac{5}{6} xy - \frac{1}{3} x^{2} +\frac{1}{4} y^{2} )=$

Agrupamos los términos semejantes :

$(\frac{5}{6} x^{2} -\frac{1}{6} x^{2} -\frac{1}{3} x^{2} )+ (\frac{3}{4} xy-\frac{1}{2} xy +\frac{5}{6} xy)+ (-\frac{2}{3} y^{2} +\frac{1}{8} y^{2} +\frac{1}{4} y^{2} ) =$

Realizamos las operaciones indicadas en cada caso :

$( \frac{5x^{2}-x^{2} -2x^{2} }{6} )+ (\frac{9xy-6xy+10xy}{12} )+ (\frac{-16y^{2}+3y+6y^{2} }{24} ) =$

$(\frac{2}{6} x^{2} )+(\frac{13xy}{12} )+ (\frac{-7y^{2} }{24} )=$

$\frac{2}{6} x^{2} +\frac{13xy}{12} - \frac{7}{24} y^{2}$