Question

Despejar h $E= \frac{1}{2} m v^{2} + mgh$

Answer 1

$E = \frac{1mv^{2} }{2} +mgh$

$E - \frac{1mv^{2} }{2} = mgh$

$\frac{2E - mv^{2} }{2} = mgh$

$\frac{2E - mv^{2} }{2mg} = h$