Question

4. Hallar el valor de "x" en:

Answer 1

Respuesta:

Hallar el valor de "x" en

$\boxed{\frac{6\text{x}-2}{4}+\frac{2\text{x}-1}{3}=10}$

MCM de 4-3 = 12

$\frac{6x-2}{4}\cdot \:12+\frac{2x-1}{3}\cdot \:12=10\cdot \:12$

$\frac{6x-2}{4}\cdot \:12=6\left(3x-1\right)$

$\frac{2x-1}{3}\cdot \:12=4\left(2x-1\right)$

$10\cdot \:12=120$

$6\left(3x-1\right)+4\left(2x-1\right)=120$

$6\left(3x-1\right)+4\left(2x-1\right)=26x-10$

$26x-10=120$

$120+10=130$

$26x=130$

Solución

130/26 = 5

$\boxed{\text{x}=5}$

Saludos...