Question

resolver los siguientes sistemas lineales xfa
3x-5y=-11
x-4y=-13

Answer 1

Respuesta:

Hola las respuestas son

• $m = \frac{3}{5}$  
• $m = \frac{1}{4}$

Explicación paso a paso:

$1) 3x-5y=-11 \\\\\frac{3}{5}x + \frac{11}{5} \\\\x = (-\frac{11}{3} , 0 ) \\\\y = ( 0 , \frac{11}{5} ) \\\\ \frac{3}{5}x + \frac{11}{5} = \frac{5x - 11}{3} \\\\\frac{5x - 11}{3} : m = \frac{3}{5} \\\\m = \frac{3}{5} R// \\\\\\2) x-4y=-13 \\\\y = \frac{1}{4}x + \frac{13}{4} \\\\ \frac{1}{4}x + \frac{13}{4} \\\\ \frac{1}{4}x + \frac{13}{4} = x : ( -13 , 0 ) \\\\y = ( 0 , \frac{13}{4} ) \\\\\frac{1}{4}x + \frac{13}{4} = 4x - 13 \\\\\\m = \frac{1}{4} R//$

Espero te sirva saludos suerte