Question

hallen el valor de E.
porfavor ayudenme a resolver doy coronas​

Answer 1

RESOLUCIÓN:

$\frac{3}{P} = \frac{P}{E} = \frac{E}{R} = \frac{R}{U} = \frac{U}{96} = k$

Le damos forma:

$\frac{96 {k}^{5} }{96 {k}^{4} } = \frac{96 {k}^{4} }{96 {k}^{3} } = \frac{96 {k}^{3} }{96 {k}^{2} } = \frac{96 {k}^{2} }{96k} = \frac{96k}{96} = k$

Resolvemos:

$96 {k}^{5} = 3 \\ {k}^{5} = \frac{3}{96} \\ {k}^{5} = \frac{1}{32} \\ k = \sqrt{ \frac{1}{32} } \\ k = \frac{1}{2}$

Hallamos los que nos piden:

$E = 96 {k}^{3} \\ E = 96 \times ( \frac{1}{2} ) {}^{3} \\ E = 96 \times \frac{1}{8} \\ E = 12$

RESPUESTA:

$A) \: 12$