Question

me podrías ayudar con estas tres porfa ​

Answer 1

Explicación paso a paso:

11)

Hallamos la hipotenusa:

c² = a² + b²

c² = 4² + 2²

c² = 16 + 4

c² = 20  

c = √20  

c = 2√5

Razones trigonometricas

sen B = 4/2√5 = 4√5/10 = (2√5)/5

cos B = 2/2√5 = 2√5/10 = √5/5  

tang B = 4/2 = 2/1  

cotan B = 2/4 = 1/2  

sec B = 2√5/2 = √5

csc B = 2√5/4 = √5/2

sen C = 2/2√5 = 2√5/10 =√5/5

cos C = 4/2√5 = 4√5/10 = (2√5)/5  

tang C = 2/4 = 1/2  

cotan C = 4/2 = 2/1  

sec C = 2√5/4 = √5/2

csc C = 2√5/2 = √5