Question

se dan los siguientes complejos: z1=3-2i z2=4+1 calcular: a) z1+z2 b) z1×z2 c) z1/z2 ​

Answer 1

Respuesta:

a) z₁+z₂ = (3-2i)+(4+1) = (3-2i) + 5 = 8-2i

b) z₁xz₂ = (3-2i)x(4+1) = (3-2i)(5)= 15-10i

c) z₁/z₂= (3-2i)/(4+1) =(3-2i)/5= 3/5 - 2/5 i

Explicación paso a paso:

a) z₁+z₂ = (3-2i)+(4+1) = (3-2i) + 5 = 8-2i

b) z₁xz₂ = (3-2i)x(4+1) = (3-2i)(5)= 15-10i

c) z₁/z₂= (3-2i)/(4+1) =(3-2i)/5= 3/5 - 2/5 i