Respuestas
Respuesta dada por:
2
Primero una propiedad de los logaritmos:
![n.LogA = LogA^{n} n.LogA = LogA^{n}](https://tex.z-dn.net/?f=n.LogA+%3D+LogA%5E%7Bn%7D)
entonces:
![4.\log(\frac{x}{5}) + \log(\frac{625}{4}) = 0
\log(\frac{x}{5})^4 + \log(\frac{625}{4}) = 0
\log(\frac{x}{5})^4 = -\log(\frac{625}{4})
\log(\frac{x^{4}}{625}) = -1.\log(\frac{625}{4})
\log(\frac{x^{4}}{625}) = \log(\frac{625}{4})^{-1}
4.\log(\frac{x}{5}) + \log(\frac{625}{4}) = 0
\log(\frac{x}{5})^4 + \log(\frac{625}{4}) = 0
\log(\frac{x}{5})^4 = -\log(\frac{625}{4})
\log(\frac{x^{4}}{625}) = -1.\log(\frac{625}{4})
\log(\frac{x^{4}}{625}) = \log(\frac{625}{4})^{-1}](https://tex.z-dn.net/?f=4.%5Clog%28%5Cfrac%7Bx%7D%7B5%7D%29+%2B+%5Clog%28%5Cfrac%7B625%7D%7B4%7D%29+%3D+0%0A%0A%0A%5Clog%28%5Cfrac%7Bx%7D%7B5%7D%29%5E4+%2B+%5Clog%28%5Cfrac%7B625%7D%7B4%7D%29+%3D+0%0A%0A%5Clog%28%5Cfrac%7Bx%7D%7B5%7D%29%5E4+%3D+-%5Clog%28%5Cfrac%7B625%7D%7B4%7D%29%0A%0A%5Clog%28%5Cfrac%7Bx%5E%7B4%7D%7D%7B625%7D%29+%3D+-1.%5Clog%28%5Cfrac%7B625%7D%7B4%7D%29%0A%0A%5Clog%28%5Cfrac%7Bx%5E%7B4%7D%7D%7B625%7D%29+%3D+%5Clog%28%5Cfrac%7B625%7D%7B4%7D%29%5E%7B-1%7D%0A)
Cuando una fraccion esta elevada a un exponente negativo se voltea:
![\log(\frac{x^{4}}{625}) = \log(\frac{4}{625}) \log(\frac{x^{4}}{625}) = \log(\frac{4}{625})](https://tex.z-dn.net/?f=%5Clog%28%5Cfrac%7Bx%5E%7B4%7D%7D%7B625%7D%29+%3D+%5Clog%28%5Cfrac%7B4%7D%7B625%7D%29)
Por comparacion:
![\frac{x^{4}}{625} = \frac{4}{625}
x^{4} = 4
x = \pm \sqrt{2} \frac{x^{4}}{625} = \frac{4}{625}
x^{4} = 4
x = \pm \sqrt{2}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E%7B4%7D%7D%7B625%7D+%3D+%5Cfrac%7B4%7D%7B625%7D%0A%0Ax%5E%7B4%7D+%3D+4%0A%0Ax+%3D+%5Cpm+%5Csqrt%7B2%7D+)
entonces:
Cuando una fraccion esta elevada a un exponente negativo se voltea:
Por comparacion:
ssmm:
muchas gracias!
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