Question

a)7+(-3)(-4)+(-2)³(6)​

Answer 1

Respuestas:

$7+\left(-3\right)\left(-4\right)+\left(-2\right)^3\left(6\right)=-29$

$9x6:3+\left(-5\right)^2\left(-2\right)^2=\frac{54x}{103}$

$\sqrt{144}\frac{\left(-4\right)^3}{32}-\sqrt{121}\frac{\left(-3\right)^4}{27}=-57$

$\sqrt{3^4}x\left(-2\right)^3-6^2\left(-3\right)^2+2\left(-4\right)=-72x-332$

$\left(-10\right)^2+\left[-2-+5+\left(\sqrt{36}\right)\left(-7\right)\right]^2=2501$

$\left(-8\right)^5:\left(-2\right)^4+\sqrt{6x+10^2-5^2}x\left(-2\right)=-\frac{16384\left(8+\sqrt{3}x\sqrt{2x+25}\right)}{64-6x^3-75x^2}$

$\left(40-5x-7\right)^2:\left(-5\right)^2+\sqrt[3]{-27}x\left(-5\right)^3=\frac{\left(-5x+33\right)^2}{25+375x}$

$\left(-3\right)^3:\left(+27\right)+\left(\sqrt[3]{-8}\right)\left(+27\right)^0+-1=-\frac{9}{8}$

$\left(-2\right)\left(-3\right)^2+\sqrt[3]{-27}+\sqrt[5]{32}=-19$

$\sqrt[5]{-32}-\sqrt{\sqrt{9}+\sqrt{1}}:\left(-1\right)^2+\left(-7-4\right)=\frac{2}{5}$

(Espero que te haya servido de ayuda)