Question

CUADRADO DE LA DIFERENCIA DE DOS CANTIDADES
1) (3X+1/4)2=
2) (2m+2n3)2=
3) (x+y)3)=
4) (30x+1/3y)2=
5) (xm+xm+2)2=

Answer 1

(3x+1/4)²=(3x)²+2(3x)(1/4)+(1/4)²=9x²+3x/2+1/16

(2m+2n³)²=(2m)²+2(2m)(2n³)+(2n³)²=4m²+8mn³+4n⁶

(x+y)³=x³+3x²y+3xy²+y³

(30x+1/3y)²=(30x+y/3)²=30x²+20xy+y²/9

(x^m+x^m+2)²=(2x^m+2)²=4x^2m+8x^m+4

Espero que sirva!Saludos!