Question

(2-x)/3+(3-x)/4+(4-x)/5+(5-x)/6+3/4 =0
alguien q me pueda ayudar xfis

Answer 1

$\frac{2-x}{3} + \frac{3-x}{4} + \frac{4-x}{5} + \frac{5-x}{6} + \frac{3}{4} =0 \\ \\ \frac{20(2-x)}{3(20)} + \frac{15(3-x)}{4(15)} + \frac{12(4-x)}{5(12)} + \frac{10(5-x)}{6(10)} + \frac{3(15)}{4(15)} =0 \\ \\ \frac{40-20x}{60} + \frac{45-15x}{60} + \frac{48-12x}{60} + \frac{50-10x}{60} + \frac{45}{60} =0 \\ \\ \frac{228-57x}{60} =0 \\ \\ 228-57x = 60(0) \\ \\ 228 - 57x = 0 \\ \\ 228 = 57x \\ \\ 4 = x$