Question

Igualdades y Ecuaciones
$\frac{1}{5} x + 4= -12$
$x^{2} -1 = (X+1) (X-1)$
5x + 6 = 10x + 5
Aiudaaa...!

Answer 1

1) $\frac{x}{5} + 4 =-12 \\ \\ x+ 4(5)=-12(5) \\ \\ x + 20 = -60 \\ \\ x = -60-20 \\ \\ x = -80$

2) $x^{2} -1 =(x+1)(x-1) \\ \\ x^{2} -1 = x^{2} -x+x-1 \\ \\ x^{2} -1 = x^{2} -1 \\ \\ 0x =0$

3) $5x+6=10x+5 \\ \\ 6-5 = 10x-5x \\ \\ 1 = 5x \\ \\ \frac{1}{5} =x$