Question

si "θ" es agudo y se cumple que tanθ=2/3; calcular T=senθ + 12cotθ

Answer 1

tan θ = 2/3

θ = arctan(2/3)

T = sen θ + 12cot θ

T = sen(arctan(2/3)) + 12 cos(arctan(2/3)) / sen(arctan(2/3))

T = 2,05 aproximadamente