Question

cuántos números de la forma a(a+3) b(b+2) en base a 8 existen ​

Answer 1

a(a+3)b(b+2)

=(a(a+3)b)(b+2)

=(a(a+3)b)(b)+(a(a+3)b)(2)

=a²b²+3ab²+2a²b+6ab

=a²b²+2a²b+3ab²+6ab

$a(a+3)b(b+2) \\ =(a(a+3)b)(b+2) \\ =(a(a+3)b)(b)+(a(a+3)b)(2) \\ =a²b²+3ab²+2a²b+6ab \\ \color{darkred} \large{=a²b²+2a²b+3ab²+6ab}$

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