Question

Binomios conjugados , con operacion porfa ayúdenme son para mañana
(4x-2)(4x+2)=
(-3e+f)(-3e-f)=
(5a-2b)(5a+2b)=
(6x+y)(6x-y)=
(m²+1)(m²-1)=
(5a-b²)(5a+b²)=
(2a²+b)(2a²+b)=
(7e+2f²)(7e-2f²)=
(8m²-3n)(8m²+3n)=


Son binomios con un termino en común
(x+5)(x+4)=
(a+8)(a-3)=
(b-4)(b+5)=
(m-9)(m+2)=
(y-1)(y-6)=
(b+2)(b+3)=
(a-3)(a-4)=
(m+2)(m-5)=
(y+9)(y-8)=
(x-6)(x-5)=
(a+3)(a+2)=
(m-5)(m-1)=
(y+4)(y-5)=

Answer 1

Respuesta:

(4x-2) (4x+2)= (4x-2)

(-3e+f) (-3e-f)= (3e-f)

(5a-2b)(5a+2b)= (5a-2b)

(6x+y)(6x-y)=(6x-y)

(m²+1)(m²-1)=(m^2 -1)

(5a-b²)(5a+b²)=(5a-b^2)

(2a²+b)(2a²+b)=(2a^2+b)

(7e+2f²)(7e-2f²)=(76-2f^2)

(8m²-3n)(8m²+3n)=(8m^2-3n)

Espero que te sirva :)