Question

$x^{2} = x- 1/4$

Answer 1

$Hola \\ \\ x^{2} =x- \frac{1}{4} \\ \\ 4x^{2}-4x+1=0~--\ \textgreater \ \frac{-b\pm \sqrt{b\²-4ac} }{2a} \\ \\ sendo: \\ a=4 \\ b=-4 \\ c=1 \\ x= \frac{4\pm \sqrt{(-4)\²-4.4.1} }{2.(4)} \\ \\\boxed{\boxed{ x= \frac{1}{2}}}$