Question

AYUDA POR FA CON PROCEDIMIENTO

Answer 1

Primero hacemos por partes:
 = 7²x7^50 = 7^52

49 = 7^2

= 7^52x7^2 = 7^54

42 = 7x6: (7^1)(6^1)

(7^60)/(7^7) = (7^53)

= 7^54+(7^1)(6^1).[7^53]

= 7^54 + (7^54)(6^1)

= 7^54.[1 + 6]

= 7^54.[7]

= 7^55

 

Answer 2

$7^{2} 7^{50}49+42( \frac{7^{60} }{ 7^{7} })$
$7^{2} 7^{50} 7^{2}+42( 7^{60-7})$
$7^{2+50+2}+42( 7^{53} )$
$7^{54}+(2)(3)(7)( 7^{53})$
$7^{54}+(6)( 7^{54})$
$7^{54}[1+6]$
$7^{54}[7]$
$7^{55}$