Question

3x+y+z=1
x+2y-z=1
x+y+2z=-17

Procedimiento

Answer 1

Respuesta:

$\begin{bmatrix}3x+y+z=1\\ x+2y-z=1\\ x+y+2z=-17\end{bmatrix}$

$\begin{bmatrix}\frac{1-y-z}{3}+2y-z=1\\ \frac{1-y-z}{3}+y+2z=-17\end{bmatrix}$

$\begin{bmatrix}\frac{5y-4z+1}{3}=1\\ \frac{2y+5z+1}{3}=-17\end{bmatrix}$

$\begin{bmatrix}\frac{2\cdot \frac{4z+2}{5}+5z+1}{3}=-17\end{bmatrix}$

$\begin{bmatrix}\frac{11z+3}{5}=-17\end{bmatrix}$

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$y=\frac{4\left(-8\right)+2}{5}$

$y=-6$  <==

______________________________

$x=\frac{1-\left(-6\right)-\left(-8\right)}{3}$

$x=5$ <==

______________________________

$11z+3-3=-85-3$

$11z=-88$

$z=-8$ <==

Explicación paso a paso:

espero te sirva, coronita plis :)