Question

Hacerme los trapecios por favor los 4

Answer 1

PROBLEMA "a"

$A = ( \frac{10 \: cm + 6 \: cm}{2} ) \times ( \sqrt{(3 \: cm) {}^{2} - (2 \: cm) {}^{2} } ) \\ A = ( \frac{16 \: cm}{2} ) \times \sqrt{5} \: cm \\ A = 8 \: cm \times \sqrt{5} \: cm \\ A = 8 \sqrt{5} \: cm {}^{2} \\ A = 17.92 \: {cm}^{2}$

PROBLEMA "b"

$A = ( \frac{7 \: m + 7 \: m + 2( \sqrt{(4.13 \: m) {}^{2} - (3.5 \: m) {}^{2} }) }{2} ) \times 3.5 \: m \\ A = ( \frac{14 \: m+ 2(2.19246 \: m)}{2} ) \times 3.5 \: m \\ A = ( \frac{18.38492 \: m}{2} ) \times 3.5 \: m \\ A = 9.19246 \: m \times 3.5 \: m \\ A = 32.17 \: {m}^{2}$

PROBLEMA "c"

$A = ( \frac{24 \: m + 16 \: m}{2} ) \times \sqrt{( \sqrt{164} \: m) {}^{2} - ({4})^{2} } \\ A = ( \frac{40 \: m}{2} ) \times ( \sqrt{164 \: {m}^{2} - 16 \: {m}^{2} } ) \\ A = 20 \: m \times \sqrt{148} \: m \\ A = 243.4 \: {m}^{2}$

PROBLEMA "d"

$A = ( \frac{14 \: m + (14 \: m- 4 \: m - 4 \: m)}{2} ) \times 3 \: m \\ A = ( \frac{14 \: m + 6 \: m}{2} ) \times 3 \: m \\ A = ( \frac{20 \: m}{2} ) \times 3 \: m \\ A = 10 \: m \times 3 \: m \\ A = 30 \: {m}^{2}$