Question

ayuda con matematicas paso a paso

Answer 1

Propiedad:

$[\frac{x}{y}] ^{-a}$ = $[\frac{y}{x} ]^a$

Solucion:

1.

= $(\frac{3}{2} )^{-2}$ : $(\frac{2}{3} )^{-3}$

= $(\frac{2}{3}) ^2$ : $(\frac{3}{2} )^3$

= $\frac{2^2}{3^2}$ : $\frac{3^3}{2^3\\}$

= $\frac{4}{9}$ : $\frac{27}{8}$

= $\frac{4}{9}$ × $\frac{8}{27}$

= $\frac{32}{243}$

2.

= $[(\frac{2}{3} )^{2}]^{3}$

= $[\frac{2}{3}]^{2.3}$

= $[\frac{2}{3}]^{6}$

3.

= $[[(\frac{2}{3} )^2]^3]^{-4}$

= $(\frac{2}{3} )^{2.3.-4}$

= $(\frac{2}{3} )^{-24}$

4.

= $(\frac{4}{9} )^{-2} :(\frac{27}{8} )^{-3}$

= $(\frac{9}{4} )^{2}$ : $(\frac{8}{27} )^{3}$

Espero te haya ayudado:)