Question

ENCONTRAR LA DERIVADA​

Answer 1

Respuesta:

f(x) = (4x+1)(10x^2-5)

f ' (x) = d/dx[ (4x+1)(10x^2-5) ]

f ' (x) = d/dx(4x+1)×(10x^2-5)+(4x+1)×d/dx[ (10x^2-5) ]

f ' (x) = ( d/dx[4x]+d/dx[1])×(10x^2-5)+(4x+1)×(d/dx[10x^2]-d/dx[5])

f ' (x) = ( 4×d/dx[x]+0 ) ×(10x^2-5)+(4x+1)×(10×d/dx[x^2]-0)

f ' (x) = (4(1)+0)×(10x^2-5)+(4x+1)×(10(2x))

f ' (x) = 4(10x^2-5)+(4x+1)×(20x)

f ' (x) = 40x^2-20+80x^2+20x

f ' (x) = 120x^2+20x-20

Explicación paso a paso: