Question

resuelve:
x² - y²=
a² - 4 =
1 - m² =
a² - 25=
4a² - 9=
a² b∧8 - c²=
a∧10 - 49b∧12=

Answer 1

Factorizar.

Caso.
Diferencia de cuadrados.


Aplicas.
a² - b² = (a + b)(a - b)

x² - y² =
(x + y)(x - y)

a² - 4 =
a² - 2² =
(a + 2)(a - 2)

1 - m² =
1² - m² =
(1 + m)(1 - m)

a² - 25 =
a² - 5² =
(a + 5)(a - 5)

4a² - 9 =
2²a² - 3² =
(2a + 3)(2a - 3)

a²b⁸ - c² =
a²(b⁴)² - c² =
(ab⁴ + c)(ab⁴ - c)


a¹⁰ - 49b¹² =
(a⁵)² - 7²(b⁶)² =
(a⁵ + 7b⁶)(a⁵ - 7b⁶)

Answer 2

x² - y² = (x+y)(x-y)

a² - 4 = (a+2)(a-2)

1 - m² = (1+m)(1-m)

a² - 25 = (a+5)(a-5)

4a² - 9 = (2a+3)(2a-3)


$a^{2}b^{8} - c^{2} = (ab^{4} +c)(ab^{4}-c)$


$a^{10} - 49 b^{12} = ( a^{5} +7 b^{6}) ( a^{5} -7 b^{6})$