Question

ayudais pls 6to primaria u-u

Answer 1

Respuesta:

2. 1

3. 1

5. 81/225

8. 7

Explicación paso a paso:

2. Cos θ = $\sqrt{3}/2$

$Cos^{2}$ θ + 1/4

$(\sqrt{3})^{2} /2^{2}$ + 1/4

$3 /4$ $+ 1/4 = (3 + 1)/4 = 4/4 = 1$

3. Sen θ = 5/13

$Sen ^{2}$ θ + 144/169

$(5)^{2} /13^{2}$ + 144/169

$25/169$ $25/169 + 144/169 = (25+144)/169 = 169/169 = 1$

5.

$12^{2}+x^{2} =15^{2}\\ 144+x^{2} =225\\ x^{2} =225-144\\ x^{2} =81\\ x=\sqrt{81} \\ x=9$

$(Sen\beta )^{2} =(\frac{9}{15} )^{2}$

$(Sen\beta )^{2} =\frac{81}{225}$

8. $Sen\beta =\frac{\sqrt{3} }{2}$

$6\sqrt{3}(\frac{\sqrt{3} }{2})-2\\= 6(\frac{\sqrt{3}^{2} }{2})-2\\=6(3)/2-2\\=18/2-2\\=9-2\\=7$