Question

como se balancea esta ecuacion •ClO3- + N2H4 → NO + Cl- por el metodo de ion electron les agradezco gracias

Answer 1

  ₊₅ ₋₂         ₋₂ ₊₁        ₊₂₋₂      ₋₁
(ClO3)⁻ + N2H4 → NO + (Cl)⁻
   
    ₊₅ ₋₂                                  ₋₁
  (ClO3)⁻ + 6H2O + 6 e⁻ → (Cl)⁻  + 6(OH⁻)  + 3H2O      OXIDACCION
  ₋₂ ₊₁                        ₊₂₋₂     
 N2H4 + 2H2O + 8(OH⁻) → 2NO + 8 H2O +8e⁻             REDUCCION
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intercambiar electrones

₊₅ ₋₂                                  ₋₁
  (ClO3)⁻ + 6H2O + 6 e⁻ → (Cl)⁻  + 6(OH⁻)  + 3H2O      8 e⁻ Ι 2 = 4
  ₋₂ ₊₁                        ₊₂₋₂     
 N2H4 + 2H2O + 8(OH⁻) → 2NO + 8 H2O +8e⁻             6 e⁻  Ι 2= 3
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4(ClO3)⁻ + 24 H2O + 24 e⁻ → 4(Cl)⁻ + 24 (OH⁻) + 12 H2O
3N2H4 + 6 H2O + 24 (OH⁻) →6NO + 24 H2O + 24 e⁻
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4(ClO3)⁻ + 3N2H4  → 4(Cl)⁻ + 6NO + 6H2O