Question

$\frac{7}{3- \sqrt{2} }$

Answer 1

$\frac{7}{3- \sqrt{2} } = \frac{7(3+ \sqrt{2} )}{(3- \sqrt{2})(3+ \sqrt{2} ) } = \frac{7(3+ \sqrt{2} )}{9 - 2} =\frac{7(3+ \sqrt{2} )}{7} = 3+ \sqrt{2}$