Question

Ayudaa
La necesito urgente pls :(

Answer 1

Respuesta:

$At = 300\sqrt{5} \pi + 500\pi cm^{2}$    ;     La opción :  C )

Explicación paso a paso:

Generatriz: g = 30 cm

Aitura: h = 20 cm

Radio: r

$r^{2} = g^{2} - h^{2} = (30cm)^{2} - (20cm)^{2} = 900 cm^{2} - 400cm^{2} = 500cm^{2}$

$r^{2} = 500 cm^{2}$

Area total del cono: At= ?

At =

$\pi rg + \pi r^{2} = \pi ( \sqrt{500 } )(30) + \pi ( 500) =\pi ( 10\sqrt{5} )(30)+ \pi (500) = 300\sqrt{5} \pi + 500\pi cm^{2}$

At = $300\sqrt{5} \pi +500\pi cm^{2}$