Question

considera la funcion exponencial f(x)=3^x y calculaa) F(2)b)f(-2)C)f(1/2)D) f(-3/4)

Answer 1

f(x)=3^x

a)
f(2)=3^2
f(2) =9

b)
f(-2)=3^-2
f(-2)=1/3^2
f(-2) =1/9

c )
f(1/2)=3^(1/2)
f(2)=√3

d)
f(-3/4)=3^(-3/4)
f(-3/4)=1/3^(3/4)
f(-3/4)=1/(4√3³)
f(-3/4)=1/(4√27)

Answer 2

Si f(x) = 3^x
a) f(2) = 3[tex] x^2 = 9
 b) f(-2)= 3^-2 = 1/9
c) f(1/2) = 3 x^{1/2} = \sqrt{3} 
d) f(-3/4) = 3^{-3/4} = 1 / \sqrt[4]{27}