Question

16. Resuelve:a) 6 (7-x) = 8 (6-x)b) -8 (10-x) = -6c) (x+) . 3 = (13-x) . 4 + 3d) 3 (1-2x) + 12 = 10 - 2 (x-3)e) 4 (x-6) = 12 - (x+3)f) -2 (x+3) - 4 = 18 + 4xg) 2 (3x+1) -x + 6 = 2 (x-1)h) 6x -2 (x-3) = 12Ejercicios del álgebra de Baldor.Pagina 128; ejercicio 79.13579Busquen el álgebra de Baldor en Internet.Ayudaaaa porfaaa que es para mañana...!!!  Gracias.??

Answer 1

6 (7-x) = 8 (6-x)
42 - 6x = 48 - 8x
8x - 6x = 48 - 42
2x = 6
x = 6/2
x = 3


-8 (10-x) = -6
-80+8x = -6
8x = 80-6
8x = 74
x = 74/80
x = 37/40



3 (1-2x) + 12 = 10 - 2 (x-3)
3 - 6x + 12 = 10 -2x +6
15 -6x = 16 - 2x
15-16 = 6x - 2x
-1 = 4x
-1/4 =x


4 (x-6) = 12 - (x+3)
4x-24 = 12 - x -3
4x-24 = 9-x
4x+x = 9 + 24
5x = 33
x =33/5


-2 (x+3) - 4 = 18 + 4x
-2x-6 - 4 = 18 +4x
-2x -10 = 18 + 4x
-10-18 = 4x+2x
-28 = 6x
-28/6 = x
-14/3 = x


2 (3x+1) -x + 6 = 2 (x-1)
6x + 2 - x + 6 = 2x - 2
5x + 8 = 2x - 2
5x-2x = -8-2
3x = -10
x = -10/3


6x -2 (x-3) = 12
6x-2x+6 = 12
4x = 12-6
4x = 6
x = 6/4
x= 2/3