Question

la ecuacion de los puntos que pasa por la recta? p1 ( 2, 4) y p2 (3, 6). p1 ( -2, 4) y p2 (2, 5). p1 ( 2, -3) y p2 (-4, 3). , ayuda porfa?

Answer 1

a) (2 , 4); (3 , 6)

[(X - X1)/(X2 - X1)] = [(Y - Y1)/(Y2 - Y1)]

Donde: X1 = 2; Y1 = 4;  X2 = 3; Y2 = 6

[(X - 2)/(3 - 2)] = [(Y - 4)/(6 - 4)]

(X - 2)/(1) = (Y - 4)/(2)

2(X - 2) = (Y - 4)

2X - 4 = Y - 4

Y = 2X Ecuacion de la recta

b)  ( -2, 4);(2, 5)

[(X - X1)/(X2 - X1)] = [(Y - Y1)/(Y2 - Y1)]

Donde: X1 = -2; Y1 = 4; X2 = 2; Y2 = 5

[(X - (-2))/(2 - (-2))] = [(Y - 4)/(5 - 4)]

[(X + 2)/(4)] = [(Y - 4)/(1)]

(X + 2) = 4(Y - 4)

X + 2 = 4Y - 16

X + 18 = 4Y

4Y = X + 18

Y = X/4  + 18/4:  Y = X/4 + 9/2  Ecuacion de la Recta

c) ( 2, -3);(-4, 3)

[(X - X1)/(X2 - X1)] = [(Y - Y1)/(Y2 - Y1)]

Donde: X1 = 2; Y1 = -3;  X2 = -4; Y2 = 3

 
[(X - 2)/(-4 - 2)] = [(Y - (-3))/(3 - (-3))]

[(X - 2)/(-6)] = [(Y + 3)/(6)]

(X - 2)(6) = (Y + 3)(-6)

6X - 12 = -6Y - 18

6X - 12 + 18 = -6Y

6X + 6 = -6Y

Y = (6X)/-6  + 6/-6

Y = -X - 1 Ecuacion de la recta