Question

1. Un gas ocupa un volumen de 21 en condiciones normales. ¿Qué volumen ocupará esa misma masa de gas a 2 atm y 50 °C

Answer 1

Respuesta:

V1 = 2 L

P1 = 1 atm

T= 273 K CN

V2 = ?

P2 = 2 atm

T2 = 50 + 273 = 323 K

P1 V1 = P2 V2

``````````` ``````````

T1 T2

V2 = P1 V1 T2

``````````````

P2 T1

V2 = 1 atm x 2 L x 323 K

``````````````````````````````

2 atm x 273

V2 = 1.18 L