Question

2) Calcular la longitud del penmetro del triangulo, cuyo
vertice son P1 (3,9 P2 (-2;1) P3 (1-3)​

Answer 1

$distancia entre 2 puntos\\d=\sqrt {{(x_{2} -x_1})^{2} + (y_{2}- y_{1})^{2} }\\\\d_{p1-p2} =\sqrt {{(-2 - (3))^{2} + (1- (9))^{2} }\\\\}=\sqrt{25+64} = 9.43\\d_{p2-p3} =\sqrt {{(1 - (-2))^{2} + (-3- (1))^{2} }\\\\}=\sqrt{9+16} = 5\\\\d_{p1-p3} =\sqrt {{(1 - (3))^{2} + (-3- (9))^{2} }\\\\}=\sqrt{4+144} = 12.16\\\\p= 9.43+5+12.16= 26.59$Respuesta: 26.59

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